The Valhalla of special functions
Aug. 6th, 2015 11:16 pmThus the dilogarithm is one of the simplest non-elementary functions one can imagine. It is also one of the strangest. It occurs not quite often enough, and in not quite an important enough way, to be included in the Valhalla of the great transcendental functions—the gamma function, Bessel and Legendre- functions, hypergeometric series, or Riemann’s zeta function.
Don Zagier
Don Zagier
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Date: 2015-08-07 01:14 am (UTC)The asymptotic complexity is measured in the number of high-precision multiplications. For instance, if we want to compute sqrt(3) with P decimal digits of precision (for very large P), we need to carry out O(ln P) multiplications of P-digit numbers. (The fastest computation is done using Newton's method.) This complexity is denoted by O(ln P) M(P), where M(P) is the number of operations required to multiply two P-digit integers. (The best asymptotic method for that is P (ln P)^2 or something like that.)
If we want to compute cos(sqrt(3)), we still need only O(ln P) multiplications. So cosine and square root are "equally complicated". The same holds for exp, ln, arctan and other elementary functions.
Now, as far as I remember, the Bessel function has the same asymptotic complexity as elementary functions: O(ln P) M(P). However, the Gamma function and Riemann's Zeta function have much higher complexity. For instance, Riemann's Zeta function is O(P/ln P) M(P). Catalan's constant has complexity O(ln P)^2 M(P).
Euler's constant has complexity O(ln P) M(P ln P). The same complexity holds for Euler's Gamma function on rational arguments, e.g. Gamma(1/5). However, the Gamma function on general arguments, e.g. Gamma (sqrt(2)), has complexity O(P) M(P).
So, in this sense, not all functions are equal in the "Valhalla of transcendental functions".
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Date: 2015-08-07 11:00 am (UTC)(no subject)
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Date: 2015-08-07 10:56 am (UTC)http://people.mpim-bonn.mpg.de/zagier/files/doi/10.1007/978-3-540-30308-4_1/fulltext.pdf
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Date: 2015-08-07 10:59 am (UTC)(no subject)
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